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Andrew Mun

USATT#: 230141

Introduction
This page explains how Andrew Mun (USATT# 230141)'s rating went from 1618 to 1629 at the 2019 Kansas Table Tennis Fall Open held on 2 Nov 2019 - 3 Nov 2019. These ratings are calculated by the ratings processor which goes through 4 passes over the match results data for a tournament. The following values are produced at the end of each of the 4 passes of the ratings processor for Andrew Mun for this tournament.

Initial Rating Pass 1 Pass 2 Pass 3 Final Rating (Pass 4)
1618 1614 1618 1618 1629


You can click here to view a table of all the resultant values from each of the 4 passes (and the initial rating) of the ratings processor for all of the 51 players in this tournament. Sections below for further details on the initial rating and the 4 passes of the ratings processor.

Note: We use mathematical notation to express the exact operations carried out in each pass of the ratings processor below. Whenever you see a variable/symbol such as for example Xi3, we are following the convention that the superscript part of the variable (in this case "3") indicates an index (such as in a series), and it should not be misconstrued to be an exponent (which is how it is used by default).

Initial Rating
The initial rating of a player for a tournament is the rating the player received at the end of the most recent tournament prior to the current tournament. If this is the first tournament the player has ever participated in (based on our records), then the player has no initial rating.

The initial rating for 2019 Kansas Table Tennis Fall Open held on 2 Nov 2019 - 3 Nov 2019 for Andrew Mun, and its source tournament are as follows:
Initial Rating From Tournament Start Day End Day
1618 Edgeball Chicago International Table Tennis Open 26 Oct 2019 27 Oct 2019

Click here to view the details of the initial ratings for all the players in this tournament.

Pass 1 Rating
In Pass 1, we only consider all the players that come into this tournament with an initial rating while ignoring all the unrated players. If a rated player has a match against an unrated player, then that match result is ignored from the pass 1 calculations as well. We apply the point exchange table shown below to all the matches participated in by the rated players:

Point Spread Expected Result Upset Result
0 - 12 8 8
13 - 37 7 10
38 - 62 6 13
63 - 87 5 16
88 - 112 4 20
113 - 137 3 25
138 - 162 2 30
163 - 187 2 35
188 - 212 1 40
213 - 237 1 45
238 and up 0 50

Suppose player A has an initial rating of 2000 and player B has an initial rating of 2064, and they played a match against each other. When computing the impact of this match on their rating, the "Point Spread" (as it is referred to in the table above) between these two players is the absolute value of the difference their initial ratings. When the player with the higher rating wins, presumably the better player won, which is the expected outcome of a match, and therefore the "Expected Result" column applies. If the player with the lower rating wins the match, then presumably this is not expected, and therfore it is deemed as an "Upset Result" and the value from that column in the table above is used. So, in our example of player A vs player B, if player B wins the watch, then the expected outcome happens, and 5 points are added to player B's rating and 5 points are deducted from player A's rating. Looking at Andrew Mun's match results and applying the point exchange table, gives us the following result:

Andrew Mun's Wins
Winner Loser
Point Spread Outcome Gain Player USATT # Rating Player USATT # Rating
161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457
295 EXPECTED 0 Andrew Mun 230141 1618 Wai Sheng Cheng 222952 1323
394 EXPECTED 0 Andrew Mun 230141 1618 Larry Rhea 60930 1224
536 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1082
0 0 Andrew Mun 230141 0 Bailey Mull 266949 0
536 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1082
712 EXPECTED 0 Andrew Mun 230141 1618 Neil Li 230134 906
465 EXPECTED 0 Andrew Mun 230141 1618 Nex Li 230135 1153
99 EXPECTED 4 Andrew Mun 230141 1618 Kevin Tucker 264855 1519
155 EXPECTED 2 Andrew Mun 230141 1618 Subash Bhandari 215426 1463
366 EXPECTED 0 Andrew Mun 230141 1618 Xa Vang 149781 1252
181 EXPECTED 2 Andrew Mun 230141 1618 Janek De Guzman 220389 1437
415 EXPECTED 0 Andrew Mun 230141 1618 Gabriel Jiang 230131 1203
262 EXPECTED 0 Andrew Mun 230141 1618 Everett Jiao 223400 1356
161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457

Andrew Mun's Losses
Winner Loser
Point Spread Outcome Loss Player USATT # Rating Player USATT # Rating
116 EXPECTED -3 Alexander-K Anuraga 229635 1734 Andrew Mun 230141 1618
54 UPSET -13 Kevin Jiao 223618 1564 Andrew Mun 230141 1618
252 EXPECTED -0 Jon Augspurger 85529 1870 Andrew Mun 230141 1618

You can click here to view a table of outcomes and points gained/lost from all the matches with all the players in this tournament.

The "Outcome" column above, shows whether the match had an expected (player with the higher rating wins the match) or an upset (player with the higher rating loses the match) outcome. Based on this outcome, and using both the player's initial rating, we apply the point exchange table from above and show the ratings points earned and lost by Andrew Mun in the "Gain" column. Matches are separated out into two tables for wins and losses where points are gained and lost respectively. We get the following math to calculate the Pass 1 Rating for Andrew Mun:

Initial Rating Gains/Losses Pass 1 Rating
1618 + 2 + 0 + 0 + 0 + 0 + 0 + 0 + 0 - 3 + 4 + 2 + 0 + 2 - 13 + 0 + 0 + 0 + 2 =1614

You can click here to view a table of pass1 calculations for all the rated players in this tournament.

Pass 2 Rating
The purpose of this pass is solely to determine ratings for unrated players. To do this, we first look at the ratings for rated players that came out of Pass 1 to determine an “Pass 2 Adjustment”. The logic for this is as follows:

  1. We calculate the points gained in Pass 1. Points gained is simply the difference between the Pass 1 Rating and the Initial Rating of a player:

    ρi2 = Pi1 - Pi0
    where,

    Symbol Universe Description
    Pi0 Pi0+ the initial rating for the i-th player. We use the symbol P and the superscript 0 to represent the idea that we sometimes refer to the process of identifying the initial rating of the given player as Pass 0 of the ratings processor.
    Pi1 Pi1+ the Pass 1 rating for the i-th player.
    ρi2 ρi2 the points gained by the i-th player in this tournament. Note here that we use the superscript 2 to denote that this value is calculated and used in Pass 2 of the ratings processor. Further, ρi2 only exists for players who have a well defined Pass 1 Rating. For Players with an undefined Pass 1 Rating (unrated players), will have an undefined ρi2.
    i i[1,51] the index of the player under consideration. i can be as small as 1 or as large as 51 for this tournament and the i-th player must be a rated player.

  2. For rated players, Pass 1 points gained, ρi2, is used to calculate the Pass 2 Adjustment in the following way:
    1. If a player gained less than 50 points (exclusive) in pass 1, then we set that player's Pass 2 Adjustment to his/her Initial Rating.
    2. If a player gained between 50 and 74 (inclusive) points in pass 1, then we set the player's Pass 2 Adjustment to his/her Final Pass1 Rating.
    3. If a player gains 75 or more points (inclusive) in pass 1, then the following formula applies:
      • If the player has won at least one match, and lost at least 1 match in the tournament, then the player's Pass 2 Adjustment is the average of his/her Final Pass 1 Rating and the average of his/her opponents rating from the best win and the worst loss, represented using the formula below:

        αi2 = Pi1 + Bi + Wi 2 2

        where αi2 is the Pass 2 Adjustment for the current player, Pi1 is the Pass 1 Rating, Bi is the rating of the highest rated opponent against which the current player won a match, and Wi is the rating of the lowest rated opponent against which the current player lost a match.
      • If a player has not lost any of his/her matches in the current tournament, the mathematical median (rounded down to the nearest integer) of all of the player's opponents initial rating is used as his/her Pass 2 Adjustment:

        αi2 = {Pk0}

        where Pk0 is the initial rating of the player who was the i-th player's opponent from the k-th match.
        Symbol Universe Description
        i i[1,51] the index of the player under consideration. i can be as small as 1 or as large as 51 for this tournament and the i-th player must be a rated player.
        q q[1,229] the index of the match result under consideration. q can be as small as 1 or as large as 229 for this tournament and the q-th match must be have both rated players as opponents.
        g g[1,5] the g-th game of the current match result under consideration. q can be as small as 1 or as large as 5 for this tournament assuming players play up to 5 games in a match.
        Pk0 Pk0+ initial rating of the i-th player's opponent from the k-th match.


      • Therefore, the Pass 2 Adjustment for Andrew Mun is calculated as follows:
        • Given the initial rating of 1618,
        • and the Pass 1 rating of 1614,
        • the Pass 1 gain is 1614 - 1618 = -4.
        • Since the Pass 1 gain of -4 is less than 50, the Pass 2 Rating (also referred to as Pass 2 Adjustment) is reset back to the initial rating.
        • Therefore the Pass 2 Adjustment for Andrew Mun is 1618.

        You can click here to view a table of Pass 2 Adjustments for all the rated players in this tournament.

  3. After calculating the Pass 2 Adjustment for all the rated players as described above, we can now calculate the Pass 2 Rating for all the unrated players in this tournament (which is the main purpose of Pass 2). Pass 2 Rating is calculated using the following formula:
    1. If all of the matches of an unrated player are against other unrated players, then the Pass 2 Rating for that player is simply set to 1200. You can click here to view these players who received a 1200 Pass 2 Rating. Not all of Andrew Mun's matches were against unrated players. So this rule does not apply to him.
    2. For unrated players with wins and losses, where at least 1 of the opponents has an initial rating, the Pass 2 Rating is the average of the best win and the worst loss (using the Pass 2 Adjustment of all rated players) as defined by this formula here:

      Pi2 = Bi2 + Wi2 2

      where Pi2 is the Pass 2 Rating for the i-th player, Bi2 is the largest Pass 2 Adjustment (best win) of the opponenet against whom the i-th player won a match, and Wi2 is the smallest Pass 2 Adjustment (worst loss) of the opponent against whom the i-th player lost a match.
    3. For unrated players with all wins and no losses, where at least 1 of the opponents has an initial rating, the Pass 2 Rating is calculated using the following formula:
      Pi2 = Bi2 + k=0Mi-1 I(Bi2-αk2)
      where the function I(x) is defined as, \begin{equation} I(x)=\left\{ \begin{array}{ll} 10, & \text{if}\ x >= 1, x <= 50 \\ 5, & \text{if}\ x >= 51, x <=100 \\ 1, & \text{if}\ x >= 101, x <= 150 \\ 0, & \text{otherwise} \end{array}\right. \end{equation}
      where,
      Symbol Universe Description
      Pi2 Pi2+ the pass 2 rating, of the i-th player in this tournament only applicable to unrated players, where Pi0 is not defined
      Bi2 Bi2+ the largest of the Pass 2 Adjustments of opponents of the i-th player against whom he/she won a match.
      αk2 αk2+ the Pass 2 Adjustment of the player who was the opponent of the i-th player in the k-th match
      I(x) I:+ a function that maps all integers to one of the values from -- 0, 1, 5, 10.
      Mi Mi+ total number of matches played by the i-th player in this tournament
      k k[0,Mi-1]+ The index of the match of the i-th player ranging from 0 to Mi-1
    4. For unrated players with all losses and no wins, where at least 1 of the opponents has an initial rating, the Pass 2 Rating is calculated using the following formula:
      Pi2 = Wi2 + k=0Mi-1 I(Wi2-αk2)
      where I(x) is defined above and,

      Symbol Universe Description
      Pi2 Pi2+ the pass 2 rating, of the i-th player in this tournament only applicable to unrated players, where Pi0 is not defined
      Wi2 Wi2+ the smallest of the Pass 2 Adjustments of opponents of the i-th player against whom he/she lost a match.
      αk2 αk2+ the Pass 2 Adjustment of the player who was the opponent of the i-th player in the k-th match
      I(x) I:+ a function that maps all integers to one of the values from -- 0, 1, 5, 10.
      Mi Mi+ total number of matches played by the i-th player in this tournament
      k k[0,Mi-1]+ The index of the match of the i-th player ranging from 0 to Mi-1
    5. For the rated players, all the work done in Pass 1 and Pass 2 to undone and they have their ratings reset back to their initial ratings while the unrated players keep their Pass 2 Adjustment as their final Pass 2 Rating. Since Andrew Mun is a rated player, his Pass 2 Adjustment of 1618 will be ignored, along with him Pass 1 Rating of 1614 and his Pass 2 Rating will be set to his initial rating of 1618 with which he came into this tournament.


Click here to see detailed information about the Pass 2 Ratings of all the other players in this tournament.

Pass 3 Rating
Any of the unrated players who have all wins or all losses are skipped in Pass 3. Since Andrew Mun has an initial rating of 1618, he is not an unrated player, and therefore this rule does not apply to him. You can click here to view list of all the players that are skipped in this Pass 3.

Pass 3 Rating is calculated using 2 steps described below:
  1. In the first part of Pass 3, we apply the point exchange table described in Pass 1 above except this time by using all the players' Pass 2 Ratings. Looking at Andrew Mun's wins and losses and applying the point exchange table, gives us the following result:
    Andrew Mun's Wins
    Winner Loser
    Point Spread Outcome Gain Player USATT # Rating Player USATT # Rating
    161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457
    295 EXPECTED 0 Andrew Mun 230141 1618 Wai Sheng Cheng 222952 1323
    394 EXPECTED 0 Andrew Mun 230141 1618 Larry Rhea 60930 1224
    536 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1082
    0 0 Andrew Mun 230141 0 Bailey Mull 266949 0
    536 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1082
    712 EXPECTED 0 Andrew Mun 230141 1618 Neil Li 230134 906
    465 EXPECTED 0 Andrew Mun 230141 1618 Nex Li 230135 1153
    99 EXPECTED 4 Andrew Mun 230141 1618 Kevin Tucker 264855 1519
    155 EXPECTED 2 Andrew Mun 230141 1618 Subash Bhandari 215426 1463
    366 EXPECTED 0 Andrew Mun 230141 1618 Xa Vang 149781 1252
    181 EXPECTED 2 Andrew Mun 230141 1618 Janek De Guzman 220389 1437
    415 EXPECTED 0 Andrew Mun 230141 1618 Gabriel Jiang 230131 1203
    262 EXPECTED 0 Andrew Mun 230141 1618 Everett Jiao 223400 1356
    161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457

    Andrew Mun's Losses
    Winner Loser
    Point Spread Outcome Loss Player USATT # Rating Player USATT # Rating
    116 EXPECTED -3 Alexander-K Anuraga 229635 1734 Andrew Mun 230141 1618
    54 UPSET -13 Kevin Jiao 223618 1564 Andrew Mun 230141 1618
    252 EXPECTED -0 Jon Augspurger 85529 1870 Andrew Mun 230141 1618

    You can click here to view a table of outcomes and points gained/lost from all the matches with all the players in this tournament for Pass 3 Part 1.

    The "Outcome" column above, shows whether the match had an expected (player with the higher rating wins the match) or an upset (player with the higher rating loses the match) outcome. Based on this outcome, and using both the player's Pass 2 Rating, we apply the point exchange table from above and show the rating points earned and lost by Andrew Mun in the "Gain" column. Matches are divided up into two tables for wins and losses where points are "Gain"ed for the wins and "loss"ed for losses. Putting all the gains and losses together, we get the following math to calculate the rating for Andrew Mun in this first part of Pass 3:

    Pass 2 Rating Gains/Losses Pass 3 Part 1 Rating
    1618 + 2 + 0 + 0 + 0 + 0 + 0 + 0 + 0 - 3 + 4 + 2 + 0 + 2 - 13 + 0 + 0 + 0 + 2 =1614


    You can click here to view a table of these calculations for all the players in this tournament.

  2. Given the Pass 3 Part 1 rating calculated above, the second part of Pass 3 looks very similar to the part of Pass 2 that deals with rated players where we calculate their Pass 2 Adjustment.
    1. First, we calculate the points gained in Pass 3 Part 1. Points gained is simply the difference between the Pass 3 Part 1 Rating and the Pass 2 Rating of a player:

      ρi3 = pi3 - Pi2
      where,

      Symbol Universe Description
      Pi2 Pi2+ the Pass 2 Rating for the i-th player.
      pi3 pi3+ the Pass 3 Part 1 rating for the i-th player. (Note that since this is an intermediate result, we are using a lower case p instead of the upper case P that we use to indicate final result from each pass of the ratings processor.
      ρi3 ρi3 the points gained by the i-th player in this tournament in Pass 3.
      i i[1,51] the index of the player under consideration. i can be as small as 1 or as large as 51 for this tournament.

  3. Pass 3 points gained, ρi3, is then used to calculate the Pass 3 Part 2 Rating in the following way:
    1. If a player gained less than 50 points (exclusive) in Pass 3 Part 1, then we set that player's Pass 3 Part 2 Rating to his/her Pass 2 Rating.
    2. If a player gained between 50 and 74 (inclusive) points in Pass 3 Part 1, then we set the player's Pass 3 Part 2 Rating to his/her Pass 3 Part 1 Rating.
    3. If a player gains 75 or more points (inclusive) in Pass 3 Part 1, then the following formula applies:
      • If the player has won at least one match, and lost at least 1 match in the tournament, then the player's Pass 3 Part 2 Rating is the average of his/her Pass 3 Part 1 Rating and the average of his/her opponents rating from the best win and the worst loss, represented using the formula below:

        αi3 = pi3 + Bi3 + Wi3 2 2

        where αi3 is the Pass 3 Part 2 Rating for the current player, pi3 is the Pass 3 Part 1 Rating, Bi3 is the rating of the highest rated opponent against which the current player won a match, and Wi is the rating of the lowest rated opponent against which the current player lost a match.
      • If a player has not lost any of his/her matches in the current tournament, the mathematical median (rounded down to the nearest integer) of all of the player's opponents rating is used as his/her Pass 3 Part 2 Rating:
        αi3 = {pk3}

        where pk3 is the Pass 3 Part 1 Rating of the i-th player's opponent from the k-th match.

      • Therefore, the Pass 3 Part 2 Rating for Andrew Mun is calculated as follows:
        • Given the Pass 2 Rating of 1618,
        • and the Pass 3 Part 1 rating of 1614,
        • the Pass 3 Part 1 gain is 1614 - 1618 = -4.
        • Since the Pass 3 Gain of -4 is less than 50, the Pass 3 Part 2 Rating is reset back to the Pass 2 Rating.
        • Therefore the Pass 3 Part 2 Rating for Andrew Mun is 1618.

      The Pass 3 Part 2 rating ends up becoming the final Pass 3 rating (also referred to as the Pass 3 Adjustment) except as follows:
      • In the cases where the Pass 3 Part 2 rating is less than the players' initial rating Pi0, the Pass 3 rating is reset back to that players initial rating. Andrew Mun's Pass 3 Part 2 Rating came out to 1618. Since this value is greater than Andrew Mun's initial rating of 1618, his Pass 3 Adjustment is set to his Pass 3 Part 2 Rating of 1618.

      • It is possible for the admin of this tournament to override the Pass 3 Adjustment calculated above with a value they deem appropriate. Andrew Mun does not have a manually overridden value for his Pass 3 Adjustment, therefore the value remains at 1618.
      You can click here to view a table of Pass 3 Part 2 Ratings for all the players in this tournament along with any manually overridden values.

Pass 4 Rating
Pass 4 is the final pass of the ratings processor. In this pass, we take the adjusted ratings (Pass 3 Adjustment) of all the rated players, and the assigned rating of unrated players (Pass 2 Rating), and apply the point exchange table to the match results based on these ratings to arrive at a final rating. Looking at Andrew Mun's match results and applying the point exchange table, gives us the following result:

Andrew Mun's Wins
Winner Loser
Point Spread Outcome Gain Player USATT # Rating Player USATT # Rating
161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457
295 EXPECTED 0 Andrew Mun 230141 1618 Wai Sheng Cheng 222952 1323
394 EXPECTED 0 Andrew Mun 230141 1618 Larry Rhea 60930 1224
484 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1134
646 EXPECTED 0 Andrew Mun 230141 1618 Bailey Mull 266949 972
484 EXPECTED 0 Andrew Mun 230141 1618 Mark A Newkirk 223403 1134
599 EXPECTED 0 Andrew Mun 230141 1618 Neil Li 230134 1019
465 EXPECTED 0 Andrew Mun 230141 1618 Nex Li 230135 1153
99 EXPECTED 4 Andrew Mun 230141 1618 Kevin Tucker 264855 1519
35 EXPECTED 7 Andrew Mun 230141 1618 Subash Bhandari 215426 1583
366 EXPECTED 0 Andrew Mun 230141 1618 Xa Vang 149781 1252
181 EXPECTED 2 Andrew Mun 230141 1618 Janek De Guzman 220389 1437
415 EXPECTED 0 Andrew Mun 230141 1618 Gabriel Jiang 230131 1203
202 EXPECTED 1 Andrew Mun 230141 1618 Everett Jiao 223400 1416
161 EXPECTED 2 Andrew Mun 230141 1618 Sai Krishna Gopalam 217741 1457

Andrew Mun's Losses
Winner Loser
Point Spread Outcome Loss Player USATT # Rating Player USATT # Rating
116 EXPECTED -3 Alexander-K Anuraga 229635 1734 Andrew Mun 230141 1618
107 EXPECTED -4 Kevin Jiao 223618 1725 Andrew Mun 230141 1618
252 EXPECTED -0 Jon Augspurger 85529 1870 Andrew Mun 230141 1618

You can click here to view a table of outcomes and points gained/lost from all the matches with all the players in this tournament.

The "Outcome" column above, shows whether the match had an expected (player with the higher rating wins the match) or an upset (player with the higher rating loses the match) outcome. Based on this outcome, and using both the players' Pass 3 Adjustment, we apply the point exchange table from above and show the ratings points earned and lost by Andrew Mun in the "Gain" and "Loss" columns. Matches are separated out into two tables for wins and losses where points are gained and lost respectively. We get the following math to calculate the Pass 4 Rating for Andrew Mun:

Pass 3 Rating Gains/Losses Pass 4 Rating
1618 + 2 + 0 + 0 + 0 + 0 + 0 + 0 + 0 - 3 + 4 + 7 + 0 + 2 - 4 + 0 + 0 + 1 + 2 =1629

You can click here to view a table of Pass 4 calculations for all the players in this tournament.